You are teaching a
course and must cover n (1<=n<=1000) topics. The length of each lecture
is L (1<=L<=500) minutes. The topics require t1,t2,…,tn
(1<=ti<=L) minutes each. For each topic, you must decide in which lecture
it should be covered. There are two scheduling restrictions:
1. Each topic must
be covered in a single lecture. It cannot be divided into two lectures. This
reduces discontinuity between lectures.
2. Topic i must be
covered before topic i +1 for all 1<=i<=n. Otherwise, students may not
have the prerequisites to understand topic i+1.
With the above
restrictions, it is sometimes necessary to have free time at the end of a
lecture. If the amount of free time is at most 10 minutes, the students will be
happy to leave early. However, if the amount of free time is more, they would
feel that their tuition fees are wasted. Therefore, we will model the dissatisfaction
index (DI) of a lecture by the formula:
0 if t=0,
DI = -C if
1<=t<=10,
(t-10)2 otherwise,
where C is a
positive integer, and t is the amount of free time at the end of a lecture. The
total dissatisfaction index is the sum of the DI for each lecture.
For this problem,
you must find the minimum number of lectures that is needed to satisfy the
above constraints. If there are multiple lecture schedules with the minimum
number of lectures, also minimize the total dissatisfaction index.
Input
The input consists
of a number of cases. The first line of each case contains the integer n, or 0
if there are no more cases. The next line contains the integers L and C. These
are followed by n integers t1,t2,…,tn.
Output
For each case,
print the case number, the minimum number of lectures used, and the total
dissatisfaction index for the corresponding lecture schedule on three separate
lines. Output a blank line between cases.
Sample Input
6
30 15
10
10
10
10
10
10
10
120 10
80
80
10
50
30
20
40
30
120
100
0
|
Sample Output
Case 1:
Minimum number
of lectures: 2
Total
dissatisfaction index: 0
Case 2:
Minimum number
of lectures: 6
Total
dissatisfaction index: 2700
|